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+# Do not track auto-generated files.
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+\documentclass[a4paper,12pt]{article}
+
+
+% For latex basics, see http://www.docs.is.ed.ac.uk/skills/documents/3722/3722-2014.pdf.
+% For help on symbols, see https://oeis.org/wiki/List_of_LaTeX_mathematical_symbols.
+% For info on state machines, look up youtube "Neso Academy" channel.
+
+
+% Import Packages.
+% Multi-column package. Allows formatting in columns.
+\usepackage{multicol}
+
+
+% Adjust page margins to not be so excessive.
+\addtolength{\oddsidemargin}{-.2in}
+\addtolength{\evensidemargin}{-.2in}
+\addtolength{\textwidth}{.4in}
+\addtolength{\topmargin}{-.8in}
+\begin{document}
+	\title{CS6530 Assignment 1 Report}
+	\author{Brandon Rodriguez}
+	\date{\today}
+	\maketitle
+
+	\vspace{-3ex}~
+	All answers are acquired from associated Python program, which was written from scratch for this assignment. See readme.md at project root for documentation on running it.	
+	
+	\section* {Question 1}
+	
+	\subsection{Midterm Score Calculations}
+	\vspace{-2ex}~
+	\textbf{\scriptsize Rounded to nearest 2 decimal places.}\\
+	\\
+	Max: 100 \\
+	Min: 37 \\
+	Q1: 77.0 \\
+	Median: 77.0 \\
+	Q3: 77.0 \\
+	Mean: 76.72 \\
+	Mode: 77 \\
+	Variance: 173.11 \\
+	
+	\subsection{Final Score Calculations}
+	\vspace{-2ex}~
+	\textbf{\scriptsize Rounded to nearest 2 decimal places.}\\
+	\\
+	Max: 100 \\
+	Min: 35 \\
+	Q1: 89.0 \\
+	Median: 89.0 \\
+	Q3: 89.5 \\
+	Mean: 87.08 \\
+	Mode: 97 \\
+	Variance: 119.11 \\
+	
+	
+	\section* {Question 2}
+	
+	\subsection{Compare Variance before and after Normalization}
+	\vspace{-2ex}~
+	\textbf{\scriptsize Rounded to nearest 4 decimal places.}\\
+	\\
+	Orig Midterm Score Variance: 173.1058 \\
+	Z-Score Normalized Midterm Variance: 0.999$\bar{9}$ \\
+	\\
+	Orig Final Score Variance: 119.1129 \\
+	Z-Score Normalized Final Score Calculations: 1.0
+	
+	\subsection{Normalized value of an original score of 90}
+	\vspace{-2ex}~
+	\textbf{\scriptsize Rounded to nearest 4 decimal places.}\\
+	\\
+	Record 223 has both a original midterm and original final of 90.\\
+	\\
+	Normalized, this comes to:\\
+	Midterm: 1.0097 \\
+	Final: 0.2672 \\
+	
+	We have two different values because we're using z-score normalization, which normalizes around the mean and standard deviation.
+	
+	If we used a different normalization, such as "Min-Max" normalization, then we'd have much closer normalized values. Note that because the minimum scores of "midterm" and "final" are different, "Min-Max" won't give identical normalized values for 90 either. But it will be a lot closer than z-score.
+	
+	\subsection{Pearson's Correlation Coefficient}
+	Person's Correlation Coeficient: 0.544424742312412
+	
+	\subsection{Covariance Value}
+	Covariance: 78.25419419419427
+	
+	\pagebreak
+	\section* {Question 3}
+	
+	\subsection{Jaccard Coefficient}
+	Jaccard Coefficient: 0.32222222222222224
+	
+	\subsection{Minkowski Distance}
+	h of 1: 6152.0\\
+	h of 2: 715.3278968417211\\
+	h of $\infty$: 170.0\\
+	
+	\subsection{Cosine Similarity}
+	Cosine Similarity: 0.8414040256623078
+
+	\subsection{Kullback-leibler Divergence}
+	Kullback-Leibler Divergence: 0.19420536448348794
+	
+	\vspace{4ex}
+	\section* {Question 4}
+	Expected Table:\\
+	\lbrack ~~ 8.94436519, ~ 181.05563481\rbrack\\
+ 	\lbrack 156.05563481, 3158.94436519\rbrack\\
+ 	\\
+	Chi Stat: 2450.716326822006\\
+	Degrees of Freedom: 1\\
+	P-Value: 0.0\\
+	\\
+	This indicates that there is a strong correlation, I think?
+
+\end{document}
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