From 9c47fe195e767136eb16ccd12a6a1d93a6ececf1 Mon Sep 17 00:00:00 2001
From: Brandon Rodriguez <brodriguez8774@gmail.com>
Date: Thu, 17 Nov 2016 05:39:21 -0500
Subject: [PATCH] As done of a program as I can figure out how to do, at the
current time.
I just don't understand how interupts work. Why does this magically break as soon as I attempt to interupt?
Only way to fix it seems to be to reset.
---
a8.c | 56 ++++++++++++++++++++++++++++++++++++++++++++------------
1 file changed, 44 insertions(+), 12 deletions(-)
diff --git a/a8.c b/a8.c
index c6df2fd..c0ad6d2 100644
--- a/a8.c
+++ b/a8.c
@@ -1,38 +1,58 @@
#include <msp430.h>
+char colorChange = 'r';
+
int main(void)
{
WDTCTL = WDTPW | WDTHOLD; // Watchdog timer setup.
BCSCTL1 = CALBC1_1MHZ; // Set cpu clock thingy.
DCOCTL = CALDCO_1MHZ; // More of above.
- P1DIR = BIT6; // BIT6 alternate output
+ P1DIR = BIT6; // Set P2.6 for output.
P1SEL = BIT6|BIT4; // BIT4 analog input (channel 4)
+ P2DIR = BIT1|BIT5; // Set P2.1 and 2.2 for output.
+
+ // Set interupts.
+ P1REN = BIT3; // Sets pullup state. Helps make button pushing be more consistent.
+ P1OUT |= BIT3; // Sets default output state to 1.
+ P1IE |= BIT3; // Allows interupts on 1.3 pin at all?
+ P1IES |= BIT3; // Sets interupt type for 1.3 pin?
+ P1IFG &= ~BIT3; // Enable interupts on 1.3
- TA0CTL = TASSEL_2 | MC_1 | ID_3; // use TA0.1 for PWM on P1.6
+ TA0CTL = TASSEL_2 | MC_1 | ID_3; // Timer 1 controller.
TA0CCR0 = 0x3FF; // 10-bit maximum value
TA0CCR1 = 0; // start off
TA0CCTL1 = OUTMOD_7; // reset/set output mode
- ADC10CTL1 = INCH_4 | ADC10DIV_3; // ADC10 channel 4, clock divider 3
- ADC10CTL0 = SREF_0 | ADC10SHT_3 | // VCC/VSS ref, 64 x ADC10CLKs
- ADC10ON | ADC10IE; // ADC10 enable, ADC10 interrupt enable
- ADC10AE0 = BIT4; // analog enable channel 4
+ TA1CTL = TASSEL_2 | MC_1 | ID_3; // Timer 2 controller.
+ TA1CCR0 = 0x3FF; // 10-bit maximum value
+ TA1CCR1 = 0; // start off
+ TA1CCTL1 = OUTMOD_7; // reset/set output mode
- // __enable_interrupt(); // interrupts enabled
+ ADC10CTL1 = INCH_4 | ADC10DIV_3; // ??ADC10 channel 4, clock divider 3
+ ADC10CTL0 = SREF_0 | ADC10SHT_3 | // ??VCC/VSS ref, 64 x ADC10CLKs
+ ADC10ON | ADC10IE; // ??ADC10 enable, ADC10 interrupt enable
+ ADC10AE0 = BIT4; // ??analog enable channel 4
+
+ //__enable_interrupt(); // interrupts enabled
while(1)
{
__delay_cycles(10000); // wait for ADC ref to settle
- ADC10CTL0 |= ENC + ADC10SC; // sampling and conversion start
+ ADC10CTL0 |= ENC + ADC10SC; // Sample from resistor knob thing.
// Turns cpu register off and waits for interupts.
+ //__BIS_SR(LMP4_bits | GIE);
__bis_SR_register(CPUOFF | GIE); // go to sleep with interrupts enabled
- // Can change this line to do the color interupt routines (regarding a8)? Everything else can mostly stay the same??
- // Set a variable which determines what color to change. Then if, to select other statements similar to this one?
// ADC10MEM is a 10 bit number. &-ing with 0x3F8 somehow just throws away the bottom 3 bits?
- // As they might vary too much to provide useful data, or something.
- TA0CCR1 = ADC10MEM & 0x3F8; // assigns the value held in ADC10MEM to the TA0CCR1 register
+ if (colorChange = 'r') {
+ TA0CCR1 = ADC10MEM & 0x3F8; // ADC10MEM is probably a value set from sampling, a few lines above?
+ // This will assign that value to the TA0CCR1 register, which corresponds to red?
+ } else if (colorChange == 'g') {
+ TA1CCR1 = ADC10MEM & 0x3F8; // assigns the value held in ADC10MEM to the TA0CCR1 register
+ } else {
+ //TA0CCR1 = ADC10MEM & 0x3F8; // assigns the value held in ADC10MEM to the TA0CCR1 register
+ }
}
return 0;
@@ -42,7 +62,19 @@ int main(void)
#pragma vector=ADC10_VECTOR
__interrupt void ADC10_ISR (void)
{
+
// Turns cpu register back on.
__bic_SR_register_on_exit(CPUOFF); // wake up
+
+ // If red, change to green. If green, change to blue. If blue, change to red.
+ if (colorChange == 'r') {
+ colorChange = 'g';
+ } else if (colorChange == 'g') {
+ colorChange = 'b';
+ } else {
+ colorChange = 'r';
+ }
+ P1IFG &= ~BIT3; // Enable interupts on 1.3
+
}
--
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